/*
 * If we list all the natural numbers below 10 that are multiples of 3 or 5,
 * we get 3, 5, 6 and 9. The sum of these multiples is 23.
 * 
 * Find the sum of all the multiples of 3 or 5 below 1000.
 */

package pj1;

class Problem1 {
	static final int problem = 1000;
	
	public static void main(String[] args) {
		int result = 0;
		for(int i=0; i<problem; i++) {
			result += ((i%3==0) || (i%5==0)) ? i : 0;
		}
		System.out.println(result);
	}
}
